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A solution of silver nitrate is electrolysed for 20 minutes with a current of 2 ameres. Calculate the mass of silver deposited at the cathode. |
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Answer» Solution :Electrochemical reaction at cathode is `AG^(+) + e^(-) to Ag` (reduction) `m = ZI t` `m - (108 g mol^(-1))/(96500 C mol^(-1))xx 2400 C` `m = 2.68 g` `Z = ("molarmass of Ag")/((96500)) = (108)/(1 xx 96500)` `I = 2A` `t = 20 xx 60S = 1200S` `It = 2A xx 1200 S = 2400C`. |
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