1.

A solution of sucross (molar mass = 342 g "mol"^(-1)) has been prepared by dissolving 68.4 g of sucrose in one kg of water. K_(f) for water is "1.86 K kg mol"^(-1) and vapour pressure of water at 298 K is 0.024 atm. The vapour pressure of the solution at 298 K will be

Answer»

0.230 ATM
0.233 atm
0.236 atm
0.0239 atm

Solution :`(p^(@)-p_(s))/(p^(@))=(n_(2))/(n_(1))=(w_(2)//M_(2))/(w_(1)//M_(1))`
i.e., `(0.024-p_(s))/(0.024)=(68.4//342)/(1000//18)`
`or(1000)/(18)(0.024-p_(s))=(68.4)/(342)xx0.024`
`or 0.024-p_(s)=0.000086 or p_(s)=0.0239 atm.`


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