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A solution prepared by dissolving 1.25g of oil of winter green (methyl sallicylate) in 99.0g of benzene has a boiling point of 80.31^(@)C. Determine the molar mass of this compound. (B.P. of pure benzene =80.10^(@)C and K_(b) for benzene =2.53^(@)C kg "mol".1) |
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Answer» Solution :`M_(B)=(K_(b)xxW_(B))/(DeltaT_(b)xxW_(A))` `K_(b)=2.53 K KG mol^(-1),W_(B)=1.25g, W_(A)=99.0g=0.099 kg, DeltaT_(b)=(80.31-80.10)=0.21^(@)=0.21K` `M_(B)=((2.53K kgmol^(-1))xx(1.25g))/((0.21K)xx(0.099 kg))=152.12 g mol^(-1)` |
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