1.

A solution prepared by dissolving 15 g of non-volatile solute in 270 g of water gave relative lowering of vapour pressure of 0.005. The molecular weight of the solute is

Answer»

324
200
225
20

Solution :`M_(2) = (W_2M_1)/(W_1) XX ((p^@)/(p^@ -p_s))` where, SYMBOLS havetheir usualmeaning , `M_(2) = (15 xx 18)/(270) xx (1)/(0.005) =200`


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