1.

A solution prepared by dissolving 8.95 mg of a gene fragment in 35.0 mL of water has an osmotic pressure of 0.335 torr at 25^(@)C. Assuming that the gene fragment is a non-electrolyte, calculate its molar mass.

Answer»


SOLUTION :`M_(2)=(wRT)/(PIV)=((8.95xx10^(-3)g)(0.0821"L ATM K"^(-1)"MOL"^(-1))(298K))/(("0.335/760 atm")(35xx10^(-3)L))="14193.3 g mol"^(-1)`


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