1.

A solution which is 10^(-3)M each in Mn^(2+),Fe^(2+),Zn^(2+) and Hg^(2+) is treated with 10^(-16)M sulphide ion. If K_(SP) of MnS, FeS, ZnS and HgS are 10^(-15),10^(-23),10^(-20) and 10^(-54) respectively, which one will precipitate first

Answer»

FeS
MgS
HGS
ZnS

Solution :HgS having the lowest `K_(SP)` AMONG the lot will PRECIPITATE first.


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