InterviewSolution
Saved Bookmarks
| 1. |
A solution which is `10^(-3)M` each in `Mn^(2+),Fe^(2+),Zn^(2+)` and `Hg^(2+)` is treated with `10^(-16)M` sulphide ion. If `K_(SP)` of MnS, FeS, ZnS and HgS are `10^(-15),10^(-23),10^(-20)` and `10^(-54)` respectively, which one will precipitate firstA. FeSB. MgSC. HgSD. ZnS |
|
Answer» Correct Answer - C HgS having the lowest `K_(SP)` among the lot will precipitate first. |
|