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A solution which is `10^(-3) M` each in `Mn^(2+), Fe^(2+), Zn^(2+)` and `Hg^(2+)` is treated with `10^(-16) M` sulphide ion. If `K_(sp)` of MnS, FeS, ZnS and HgS are `10^(-15), 10^(-23), 10^(-20)` and `10^(-54)` respectively, which one will precipitate first ?A. FeSB. MgSC. HgSD. ZnS |
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Answer» Correct Answer - C `HgS` will be precipitated first because [its `K_(sp)`] is minimum. |
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