1.

A solution which is 10M each in Mn^(2+),Fe^(2+), Zn^(2+) and Hg^(2+) is treated with 10^(-16) M sulphide ion. If K_(sp) of MnS, FeS, ZnS and Hgs are 10^(-15),10^(-23),10^(-20) and 10^(-54) and respectively, which one will precipitate first?

Answer»

FeS
MgS
HgS
ZnS

Solution :Hgs having the LOWEST `K_(SP)` among the lot will PRECIPITATE first.
Hence, (C) is the correct answer.


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