1.

A solutioncontaining0.513 g of naphthalene (molar mass = 128) in 50 gof C Cl_(4) gives a boiling point elevationof 0.402^(@)C whilea solutionof 0.625 g of an unknown solutegives a boilingpoint elevation of 0.650^(@)C . Findthe molar mass of the unknown solute .

Answer»


SOLUTION :Calculation of `k_(b)` :
`k_(b) = (Delta T_(b) XX w_(A) xx M_(B))/(1000 xx w_(B))`
` = (0.402 x 50 xx 128)/(1000 x 0.513) = 5.02 K m^(-1)`
`M_(B) = (5.02 xx 0.625 xx 1000)/(0.650 xx 50) =96.54`


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