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A solutionmay contain any of the following ions: Fe^(2+),Ni^(2+), Cr^(3+),Zn^(2+),Mn^(2+) Based on the experiment and result therein , which of the ions would be present? Indicate any wrong infornation if any….. a. The original solution is treated with with (NH_(4)),S(a subestitate is obtain b. The ppt for (a) dissolves in regain c. The fitrate after sepration ppt in (a) is treated with NaOH and H_(2)O_(2) A dark ppt , is separate filtrate is colourless. e. The solution from (d) is turned with aq NH_(3) A dark ppt forms f. The ppt from (e) is solution in HCI (aq) and solutiondevelops an latense red colour whentreated with SCN^(Theta) (aq) |
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Answer» Solution :Precipitate can be of `NiS` b. `NiS` dissolves in aqua regain c.Precipitatecan be of `Fe(OH)_(3)` d.`Fe(OH)_(3)` is SOLUBLE in `HCI`(aq) giving (yellow) coloured soluble of `FeCI_(3)` e.This step is INCORRECT since filtrate of (c ) isalreadly colourlessincdicatingabsence of `Cr^(2+)` f. This confims `Fe^(3+)` by forming intense redcolour `Fe^(3+) + SCN^(THETA) rarr [Fe(SCN)]^(2+)` Thus, `{:(Fe^(3+),-"confirmed"),(Ni^(2+),-"probable"),(Zn^(2+)Mn^(2+)Cr^(3+),-"ABSENT"):}` |
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