A solutionof an organiccompound was prepared bydissolving6.8 gin 100 g of water. Calculatethe osmoticpressureof thissolution at 298 Kwhenboilingpointof solutionis 100.11^(@)C . GivenK_(b) for water= 0.52 Km^(-1) and R = 0.082 litre atm k^(-1) mol^(-1)

A solutionof an organiccompound was prepared bydissolving6.8 gin 100 g

1.	A solutionof an organiccompound was prepared bydissolving6.8 gin 100 g of water. Calculatethe osmoticpressureof thissolution at 298 Kwhenboilingpointof solutionis 100.11^(@)C . GivenK_(b) for water= 0.52 Km^(-1) and R = 0.082 litre atm k^(-1) mol^(-1)
Answer» Solution :Molecularmass can be CALCULATED from boilingpointdata as : `M_(B) = (k_(b) xx w_(B) xx 1000)/(Delta T_(b) xx w_(A))` `w_(B) = 6.8 G , w_(A) = 100 g, k_(b) = 100.11 - 1000 = 0.11` `k_(b) = 0.52 K m^(-1)` `M_(B) = (0.52 xx 6.8 xx 1000)/(0.11 xx 100)` ` = 321.45` Now `"" pi = (nRT)/( V) , n = (6.8)/(321.45)` `V = 100 g ~~ 100nl = 0.1 L` `R = 0.082 L " atm " mol^(-1) K^(-1)` `R= 0.082 L " atm " mol^(-1) k^(-1)` `T = 298 K` ` pi = (6.8 xx 0.082 xx 298)/(321.45 xx 0.1)` `=5.17` atm.