1.

A sound wave has frequency 500 Hz and velocity 350 m/s . What is the distance between the two particles having phase diff. of 60^(@) .

Answer»

0.7 CM
11.6 cm
70 cm
120 cm .

Solution :v = 500 Hz, v = 350 `ms^(-1)` .
`LAMBDA = (v)/(v) = (350)/(500) = 0.7 ` m
Now x = `(lambda)/(2 PI ) . Phi = (0.7)/(2 pi ) . (pi)/(3) = 0.116 m = 11.60 m.`
or x = 11.6 cm .
Hence the correct choice is (b).


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