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A sound wave has frequency 500 Hz and velocity 350 m/s . What is the distance between the two particles having phase diff. of 60^(@) . |
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Answer» 0.7 CM `LAMBDA = (v)/(v) = (350)/(500) = 0.7 ` m Now x = `(lambda)/(2 PI ) . Phi = (0.7)/(2 pi ) . (pi)/(3) = 0.116 m = 11.60 m.` or x = 11.6 cm . Hence the correct choice is (b). |
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