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A sound wave of wavelength `0.40 m` enters the tube at `S`. The smallest radius `r` of the circular segment to hear minimum at detector `D` must be |
Answer» The path difference between the waves moving along the straight path and the semicircular path is given by `Deltaxpir-2r=(pi-2)r` For minima this path difference should be at least `(lamda)/(2)` i.e., 20, hence we have, for the minimum value of r. `(pi-2)r=20cm` or `r=(20)/(pi-2)=17.54cm` |
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