1.

A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V_0 .If the distance between the light source and photocell is made 25 cm, the new stopping potential will be

Answer»

`2V_0`
`V_0//2`
`V_0`
`4V_0`

Solution :SINCE , stopping potential is INDEPENDENT of distance hence NEW stopping potential will remain UNCHANGED i.e., neq stopping potential ` = V_0`


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