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A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V_0 .If the distance between the light source and photocell is made 25 cm, the new stopping potential will be

Answer» <html><body><p>`2V_0` <br/>`V_0//2`<br/>`V_0` <br/>`4V_0` </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> , stopping potential is <a href="https://interviewquestions.tuteehub.com/tag/independent-505826" style="font-weight:bold;" target="_blank" title="Click to know more about INDEPENDENT">INDEPENDENT</a> of distance hence <a href="https://interviewquestions.tuteehub.com/tag/new-1114486" style="font-weight:bold;" target="_blank" title="Click to know more about NEW">NEW</a> stopping potential will remain <a href="https://interviewquestions.tuteehub.com/tag/unchanged-2316761" style="font-weight:bold;" target="_blank" title="Click to know more about UNCHANGED">UNCHANGED</a> i.e., neq stopping potential ` = V_0`</body></html>


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