1.

A source of sound and a listener are approaching each other with a speed of 40ms-1 .The apparent frequency of a note produced by the source is 400 Hz. Then its true frequency is (velocity of sound in air = 360 ms-1 ) (a) 320 Hz (b) 400 Hz (c) 360 Hz (d) 420 Hz

Answer»

(a) 320 HZ

\(f' = (\frac{v+v_0}{v-v_s}) f\)

⇒ 400 = \([\frac{360+40}{360-40}]\)f

⇒ \(f\) = 320 Hz



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