InterviewSolution
Saved Bookmarks
| 1. |
A source of sound of frequency 256 Hz is moving towards a wall with a velocity of 5 m/s. How many beats per second will be heard by an observer O standing in such a positoin that the source S is between O and wall? `(c=330(m)/(s)`) |
|
Answer» Correct Answer - `7.87 Hz` Frequency reaching the wall `f_(1)=f_(0)((v)/(v-v_(s)))` Frequency received by the observer `f_(1)=f_(1),((v+v_(s))/(v))=f_(0)((v+v_(s))/(v-v_(s)))` `:.` Beat frequency `Delta f=f_(0)((v+v_(s))/(v-v_(s)))-f_(0)=256((330+5)/(330-5))-256` `=7.87 Hz` |
|