A source of sound producing wavelength 50 cm is moving away from a stationay observer with ((1)/(5) )^(th) speed of sound. Then what is the wavelength of sound received by the observer?

A source of sound producing wavelength 50 cm is moving away from a sta

1.	A source of sound producing wavelength 50 cm is moving away from a stationay observer with ((1)/(5) )^(th) speed of sound. Then what is the wavelength of sound received by the observer?
Answer» 55 CM 40 cm 60 cm 80 cm SOLUTION :Here , wavelength of the SOURCE , `lambda` = 50 cm Speed of the sound = v speed of the source , `v_(s) = (1)/(5) ` V As the source is moving away from the stationary OBSERVER, therefore the wavelength of sound received of sound received by the observer is `lambda. = ((v + v_(s))/(v)) lambda= ((V + (1)/(5) v))/(v)lambda` ` = (6)/(5) lambda = (6)/(5) xx 50 ` cm = 60 cm . correct choice is c.

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A source of sound producing wavelength 50 cm is moving away from a stationay observer with ((1)/(5) )^(th) speed of sound. Then what is the wavelength of sound received by the observer?

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