A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))/("power of" S_(1))` is equal toA. 1B. 1.02C. 10.4D. 0.98

A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000

1.	A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))/("power of" S_(1))` is equal toA. 1B. 1.02C. 10.4D. 0.98
Answer» Correct Answer - A `("power of "S_(2))/("power of"S_(1))=(n_(2)((hc)/(lamda_(2))))/(n_(1)((hc)/(lamda_(1))))=(n_(2)lamda_(1))/(n_(1)lamda_(2))=1`

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A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))/("power of" S_(1))` is equal toA. 1B. 1.02C. 10.4D. 0.98

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