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A source S_(1) produces 10^(15) photon every second having wavelength of 5000Å .Another source S_(2) produce 1.02xx10^(15) photon every second with wavelength 5100 Å product [Power of S_(1)]xx[Power of S_(2)]=…. |
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Answer» `1.00` `P_(1)=n_(1)(HC)/(lambda_(1))` Energy produced every second by `S_(2)` (Power) `P_(2)=n_(2)(hc)/(lambda_(2))` `THEREFORE (P_(2))/(P_(1))=(n_(2))/(n_(1))xx(lambda_(1))/(lambda_(2))` `=(1.02xx10^(15))/(10^(15))xx(5000)/(5100)=1.0` |
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