1.

A space station is at a height equal to the radius of the Earth . If v_Eis the escape velocity on the surface of the Earth , the same the spastation v_E

Answer»

`1/2`
`1/4`
`1/sqrt2`
`1/sqrt3`

Solution :`u_(s)=(GMm)/(2R)`
K.E = P.E
`1/2mv_(s)^(2)=(GMm)/(2R)`
`v_(s)^(2)=(GM)/R`
`v_(s)=sqrt(gR)`
But `v_(e)=sqrt(2gR)=sqrt2sqrtgR`
`v_(e)=sqrt2v_(s)`
`v_(s)=v_(e)/sqrt2`


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