A sparingly soluble salt MX is dissolved in water to prepare 1 L saturated solution.Now 10^(-6) mole NaX (assume 100% dissociation ) is added into this.Conductivity of this solution is 29xx10^(-6) S//m.If K_(sp) of MX is axx10^(-b),then find value of (a+b),a is a natural number & 1le a le 9. Given:lambda_((x)^(-))^(0)=4xx10^(-3) S m^(2) mol^(-) lambda_((Na)^(+))^(0)=5xx10^(-3) S m^(2) mol^(-) lambda_((M)^(+))^(0)=6xx10^(-3) S m^(2) mol^(-)

A sparingly soluble salt MX is dissolved in water to prepare 1 L satur

1.	A sparingly soluble salt MX is dissolved in water to prepare 1 L saturated solution.Now 10^(-6) mole NaX (assume 100% dissociation ) is added into this.Conductivity of this solution is 29xx10^(-6) S//m.If K_(sp) of MX is axx10^(-b),then find value of (a+b),a is a natural number & 1le a le 9. Given:lambda_((x)^(-))^(0)=4xx10^(-3) S m^(2) mol^(-) lambda_((Na)^(+))^(0)=5xx10^(-3) S m^(2) mol^(-) lambda_((M)^(+))^(0)=6xx10^(-3) S m^(2) mol^(-)
Answer» Solution :`MX hArrM^++X^(-)` `x " " x+10^(-6)` `[NA^+]=10^(-6) M` `K_("SOL")=K_(M^+)+K_(X^(-))+K_(Na^+)` `29xx10^(-6) = 10^3 [6xx10x +(4xx10^(-3)(x+10^(-6))+(5xx10^(-3)xx10^(-6))]` `x=2XX10^(-6)` `K_(sp)=2xx10^(-6) xx3xx10^(-6)=6XX10^(-12)`