InterviewSolution
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InterviewSolution
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A speaks truth in 605 cases and `B`speaks truth in 70% cases. The probability that they will say the samething while describing a single event is`2//19`b. `3//29`c. `17//19`d. `4//29`A. `0.56`B. `0.54`C. `0.38`D. `0.94` |
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Answer» Correct Answer - B Consider the following events: `A_(1):A` speaks truth `A_(2):B` speask truth Then, `P(A_(1)) =60//100=3//5,P(A_(2))=70//100=7//10.` For the required event, wither both of them should speak the truth of both of them should tell a lie. Thus, the required probability is `=P((A_(1)nnA_(2))uu(barA_(1)nnbarA_(2))` `=P(A_(1)nnA_(2))+P(barA_(1)nnA_(2))+P(barA_(1)nnA_(2))` `=P(A_(1))P(A_(2))+P(barA_(1))(barA_(2))` `=3/5xx7/10+(1-(7)/(10))=0.54` |
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