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A spectral line caused by the transition .^(3)D_(1) rarr ^(3)P_(0) experiences the Zeeman splitting in a weak magnetic field. When observed at right angles to the magnetic field direction, the interval between the neighbouring components of the split line is Delta omega= 1.32.10^(10) s^(-1). Find the magnetic field induction B at the point where the source is located. |
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Answer» Solution :The `.^(3)P_(0)` term does not split. The `.^(3)D_(1)` term splits into 3 lines corresponding to the shift. `DELTAE= -gmu_(B)BM_(Ƶ)` with `M_(Ƶ)=+- 1,0`. The interval between neighbouring components is then GIVEN by `ħ DELTA omega= g mu_(B)B` HENCE `B=(ħDelta omega)/(gmu_(B))` Now for the `.^(3)D_(1)` term `g=1+(1xx2+1xx2-2xx)/(2xx1xx2)=1+(4-6)/(4)=(1)/(2)` Substitution gives `B= 3.00KG= 0.3T`. |
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