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A sphere and a cube of equal volumes both are made of iron and have similar surface. If both are cool in identical surrounding, at a lower temperature, then the ratio of the initial rates of loss of heat isA. `((pi)/(6))^(1//3):1`B. `((3)/(4pi))^(-1//3):1`C. `((3)/(4pi))^(2//3):1`D. `1:1` |
Answer» Correct Answer - A Volume of sphere=Volume of cube `(4pi)/(3)r^(3)=l^(3)` `(r)/(l)=((3)/(4pi))^(1//3)` . . . (i) `((dQ)/(dt))_(S)=4pir^(2)(T^(4)-T_(0)^(4))` `((dQ)/(dt))_(C)=6l^(2)(T^(4)-T_(O)^(4))` `((dQ//dt)_(S))/((dQ//dt)_(C))=(4pir^(2))/(6l^(2))` Substitute r/l from equation (i), we have, `=(4pi)/(6)xx((3)/(4pi))^(2//3)=((pi)/(6))^(1//3)` |
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