A sphere of mass `40 kg` is attracted by a second sphere of mass `15 kg`, when their centres are `20 cm` apart, with a force of `0.1` miligram weight. Caculate the value of gravitational constant.

A sphere of mass `40 kg` is attracted by a second sphere of mass `15 k

1.	A sphere of mass `40 kg` is attracted by a second sphere of mass `15 kg`, when their centres are `20 cm` apart, with a force of `0.1` miligram weight. Caculate the value of gravitational constant.
Answer» Here `m_(1)=40kg,m_(2)=15kg` `r=0.20m` `F=0.1` miligram wt. `=0.1xx10^(-6)kg` Now `G=(Fr^(2))/(m_(1)m_(2))=((0.1xx10^(-6)xx9.8xx0.20)^(2))/(40xx15)` `=6.53xx10^(-11)Nm^(2)kg^(-2)`

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A sphere of mass `40 kg` is attracted by a second sphere of mass `15 kg`, when their centres are `20 cm` apart, with a force of `0.1` miligram weight. Caculate the value of gravitational constant.

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