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A sphere of mass `m` attached with the free end of a steel wire of length `l` swings in the veritical plane form the horizontal positon. Elongation of the wire in the vericle positon isA. `(mgl)/(Y(pi r^(2)))`B. `(2mgl)/(Y(pi r^(2)))`C. `(mgl)/(3Y(pi r^(2)))`D. `(3mgl)/(Y(pi r^(2)))` |
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Answer» Correct Answer - D `Delta l = ((F_("net")l))/(YA) , V = sqrt(2gl)` `= ((mg + (mv^(2))/(l))l)/(YA) = ((mg + 2mg)l)/(YA)` `Deltas L = (3mgl)/(Y(pi r^(2))), v = (1)/(2)Fe, U = (YA)/(2l) xx (Delta l)^(2) = (9m^(2) g^(2) l)/(2Y pi r^(2))` |
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