Saved Bookmarks
| 1. |
A spherical body of density rho is floating half immersed in liquid of density d, if alpha is the surface tension of the liquid, then the diameter of the body is |
|
Answer» `sqrt((3alpha)/(g(2rho-d)))`  WEIGHT of body = BOUYANT force + Force of suface TENSION `(4)/(3)pi r^3 rho xx g = 2/3 pi r^3 DG + 2 pi r delta ` `2/3 pi r^3 g (2 rho -d)=2 pi alpha` `So, r^2= (3 alpha)/(g(rho2p-d)` So, `r = sqrt(3 alpha)/(g(2rho -d))` |
|