1.

A spherical solid ball of volume V is made of a material of density p1 It is falling through a liquid of density p_(2) (p_(2) lt p_(1)). Assume the that the liquid applies a viscous force on the ball that is proportional to the square of its speed v, i.e., F_("viscous") = - kv^(2)(k gt 0). The terminal speed of the ball is

Answer»

<P>`dqrt((Vg(p_(1)-p_(2)))/k)`
`(Vgp_(1))/k`
`sqrt((Vgp_(1))/k)`
`(Vg(p_(1)gtp_(2)))/k`

Solution :The condition for terminal SPEED `(v_(t))` is
Weight = Buoyant FORCE + Viscous force
`thereforeVp_(1)g=Vp_(2)g+kv_(t)^(2)`
`thereforev_(t)=sqrt((V_(g)(p_(1)-p_(2)))/k)`
So Correct CHOICE is (a).


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