A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The center of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The ling PQ cuts the surface at a point O, and PO=OQ. The distance PO is equal to

A spherical surface of radius of curvature R separates air (refractive

1.	A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The center of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The ling PQ cuts the surface at a point O, and PO=OQ. The distance PO is equal to
Answer» 5R 3R 2R 1.5R Solution :The formula for SPHERICAL REFRACTING SURFACE is `(-mu_(1))/(mu)+(mu_(2))/(v)=(mu_(2)-mu_(1))/(R)` Here, `u=-x, v=+x, R=+R,mu_(1)=1, mu_(2)=1.5` `(-1)/(-x)+(1.5)/(x)=(1.5-1)/(R)` `rArrx=5R`

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