A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point and PO = OQ. The distanace PO is equal to

A spherical surface of radius of curvature R, separates air (refractiv

1.	A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point and PO = OQ. The distanace PO is equal to
Answer» 5R 3R 2R 1.5R Answer :A

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