A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and `PO=OQ`. The distance `PO`A. 5RB. 3RC. 2RD. 1.5R

A spherical surface of radius of curvature R separates air (refractive

1.	A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and `PO=OQ`. The distance `PO`A. 5RB. 3RC. 2RD. 1.5R
Answer» Correct Answer - A The formula for spherical refracting surface is `(mu_(1))/(u)+(mu_(1))/(v)=(mu_(2)-mu_(1))/R` Here `u=-x`,`v=+x`,`R=+R`,`mu_(1)=1.5` `(-1)/(-x)+(1.5)/(x)=(1.5-1)/R``implies``x=5R`

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