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                                    A thin glass (refractive index 1.5) lens has optical power of `-5D` in air. Its optical power in a liquid medium with refractive index 1.6 will beA. `-1D`B. `1D`C. `-25D`D. `25D` | 
                            
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Answer» Correct Answer - B `(1)/(f_a)=((1.5)/(1)-1)((1)/(R)-(1)/(R))` ….(i) `(1)/(f_m)=((mu_g)/(mu_m)-1)((1)/(R_1)-(1)/(R_2))` `(1)/(f_m)=((1.5)/(1.6)-1)((1)/(R_1)-(1)/(R))` ….(ii) Dividing (i) by (ii), `(f_m)/(f_a)=((1.5-1)/((1.5)/(1.6)-1))=-8` `P_a=-5=(1)/(f_a)impliesf_a=-(1)/(5)` `impliesf_m=-8xxf_a=-8xx-(1)/(5)=(8)/(5)` `P_m=(mu)/(f_m)=(1.6)/(8)xx5=1D`  | 
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