1.

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m//s^(2), the reading of the spring balance will be :

Answer»

49 N
24 N
74 N
15 N

Solution :Here, reaction of floor is `R = m(g-a)`
When the lift is STATIONARY, then `49 = m xx 9.8` or `m= 5 KG`
Hence `R = 5(9.8 - 5) = 24 N`
Hence choice is (b).


Discussion

No Comment Found

Related InterviewSolutions