A spring-block system lies inside the horizontal frictionless tube as shown in figure. At t=0, tube starts rotating with uniform angular velocity 'omega'. Initially spring was in its natural length. If the block collides with the other end of tube and the collision is perfectly elastic, then find the magnitude of block's velocity after the collidon with respect to ground. ( take k = m omega^(2) )

A spring-block system lies inside the horizontal frictionless tube as

1.	A spring-block system lies inside the horizontal frictionless tube as shown in figure. At t=0, tube starts rotating with uniform angular velocity 'omega'. Initially spring was in its natural length. If the block collides with the other end of tube and the collision is perfectly elastic, then find the magnitude of block's velocity after the collidon with respect to ground. ( take k = m omega^(2) )
Answer» `sqrt(2) OMEGA L` `sqrt( 5) omega l` `sqrt( 3) omegal` `sqrt( 6) omega l` Answer :D

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