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A spring gun has a spring constant of `80Ncm^(-1)`. The spring is compressed `12cm` by a ball of mass `15g`. How much is the potential energy of the spring ? If the trigger is pulled, what will be the velocity of ball ? |
Answer» Here, `K=80Ncm^(-1)=80xx100Nm^(-1)` `x=12cm=12xx10^(-2)m,` `m=15g=15xx10^(-3)kg` `P.E` of spring `=(1)/(2)Kx^(2)` `=(1)/(2)xx80xx100(12xx10^(-2))^(2)=57.6J` Again, KE of ball `= P.E.` of spring `(1)/(2)m upsilon^(2)=57.6, upsilon=sqrt((2xx57.6)/(15xx10^(-3)))=sqrt(7680)` `-87.6m//s` |
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