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A spring of force constant `800N//m` has an extension of 5cm. The work done in extending it from 5cm to 15cm isA. (a) 16JB. (b) 8JC. (c) 32JD. (d) 24J

Answer» Correct Answer - B
Small amount of work done in extending the spring by `dx` is
`dW=kxdx`
`:. W=kint_(0.05)^(0.15)xdx=(800)/(2)[(0.15)^2-(0.05)^2]=8J`


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