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A spring of force constant `800N//m` has an extension of 5cm. The work done in extending it from 5cm to 15cm isA. 16JB. 8JC. 32JD. 24 J |
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Answer» Correct Answer - B `W_(C)=-DeltaU` `=(U_("final")-U_("initial"))` `=-(1/2xxkxx15^(2)-1/2xxkxx5^(2))` ltBrgt `W_(c)=8` joule |
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