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A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant ofA. `(2)/(3)k`B. `(3)/(2)k`C. 3kD. 6k |
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Answer» Correct Answer - B `(1)/(k)=(1)/(k_(1))+(1)/(k_(2))or (1)/(k)=(2)/(k_(2))+(1)/(k_(2))=(3)/(k_(2))` `because" "k_(2)=3k` `because" "k_(1)=(k_(2))/(2)=(3)/(2)k` |
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