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A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then, the long piece will have a force constant of(a) \(\frac{2}{3} k\)(b) \(\frac{3}{2}k\)(c) \(3k\)(d) 6\(k\) |
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Answer» Correct answer is (b) \(\frac{3}{2} k\) |
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