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A spring of natural length 10 m and spring constant 10 N/m is connected to a ring of mass 0.1 kg, which if free to move on a frictionless horizontal bar as shown in the figure. The ring is pulled away from 'B' towards 'A' at an angle of 53^(@) with vertical, and released. Find the speed of the ring at 'C' ? |
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Answer» 90 m/s Between POSITION 'A' and 'B' `(1)/(2) k (20 - 10)^(2) - (1)/(2) k (20 - 12)^(2)` `= (1)/(2) mv^(2)` `RARR 18 k = mv^(2)` `V_(B) = sqrt((36.K)/(m)) = sqrt((36 xx 10)/(0.1)) = 60 m//s` and by smmetry : velocity at 'C' will be zero |
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