A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30^@with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?

A square coil of side 10 cm consists of 20 turns and carries a current

1.	A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30^@with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?
Answer» Solution :Torque EXERTED on current carrying pivoted rectangular COIL when SUBJECTED to external magnetic field is, `tau=BINAsintheta` (Where `theta` = angle between `vecAandvecB`) `thereforetau=BIN(l^(2))sintheta` `thereforetau=(0.8)(12)(20)(0.1)^(2)sin30^(@)" "(becausetheta=30^(@))` `thereforetau=0.96Nm`

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