InterviewSolution
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InterviewSolution
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A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30° with the direction of a uniform horizontal magnetic field of magnitude 0.8 T. What is the magnitude of the torque experienced by the coil? |
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Answer» SOLUTION :N=20 , `A=100 XX 10^(-4) m^2. 1=12 A` R=0.8 T `theta = 30^@` Torque `TAU = NI( bar A xx bar B)` `= 20 xx 12 xx 100 xx 10^(-4) xx 0.8 xx sin 30^2@` `= 20 xx 12 xx 100 xx 10^(-4) xx 0.8 xx 1/2 = 0.96 Nm` |
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