A square is placed in a uniform electric field E parallel to the horizontal such that the plane of the square makes an angle 30° with the field. If the side of the square is a, then the flux through the square wire be:(a) \(\frac{\sqrt{3} E a^{2}}{2}\)(b) \(\frac{E a^{2}}{2}\)(c) zero(d) none of these

A square is placed in a uniform electric field E parallel to the horiz

1.	A square is placed in a uniform electric field E parallel to the horizontal such that the plane of the square makes an angle 30° with the field. If the side of the square is a, then the flux through the square wire be:(a) \(\frac{\sqrt{3} E a^{2}}{2}\)(b) \(\frac{E a^{2}}{2}\)(c) zero(d) none of these
Answer» (c) zero Since electric field is acting along, plane of the square, so the angle between area vector \(\vec A\) and \(\vec E\) is 90°. These give ϕ = EAcosθ = EAcos90 = 0.