1.

A square loop of side 2cm carrying current I_(0) is placed in x-y plane in a magnetic field B= (4hat(i)+3hat(j)) T Find the unit vector along the axis about which it will start rotating.

Answer»

`(4hat(j)+3HAT(i))/5`
`(-4hat(j)-3hat(i))/5`
`(-4hat(j)+3hat(i))/5`
`(4hat(j)-3hat(i))/5`

Solution :Magnetic moment is in divection of - `za^(x)`
and`VEC(B)=4hat(i)+3hat(j)`
`vec(B)=4/5hat(i)+3/5hat(j)`
`mu=ivec(A)`
`=-(4xx10^(-4)xxI_(0))hat(k)`
`hat(tau)=muxxhat(B)`
`hat(tau)=4/5hat(j)-3/5hat(i)`
Thus the unit vector of the AXIS is `PM hat(tau)`


Discussion

No Comment Found

Related InterviewSolutions