1.

A square loop of side l carrying current I is part of the shown arrangement . Minium current I to just move the block up the inclined plane is

Answer»

`(mg sin theta+MU mg cos theta)/(BL)`
`(mg sin theta+mu mg cos theta)/(2Bl)`
`(2mg sin theta+2mu mg cos theta)/(Bl)`
`(mg sin theta-mu mg cos theta)/(Bl)`

SOLUTION :
To just move the block up,
`T=mg sin theta+mu mg cos theta`
and `""2T=Bil`
`:. i=[(2mg sin theta+2 mu mg cos theta )/(Bl)]`


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