1.

A square loop of size 2 cm is lying on a horizontal surface. A uniform magnetic field of 0.4 T is directed downward at an angle of 30^@ to the vertical as shown in the Fig. The flux linked is _____Wb.

Answer»

`8xx10^(-4)`
8
`8xx10^(-5)`
`16xx10^(-5)`

Solution :`phi=vecA.vecB`
`=AB cos theta`
`=4xx10^(-4)xx0.4xxcos60^@ "" [because A=(2XX10^(-2))^2 = 4xx10^(-4) m^2]`
`THEREFORE phi=8xx10^(-5)` WB


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