1.

A square surface of side L in the plane of the paper is placed in a uniform electric field E acting along the same. Plane at an anglethetawith the horizontal side of the square as shown in. The electric flux linked to the surface is

Answer»

` EL^(2) sin THETA `
zero
`EL^(2) `
` EL^(2) COS theta`

Solution :SINCE ` oversettoE` is in the plane of Square, HENCE `oversetto E and ` area vector ` oversetto A ` are inclined at an angleof ` 90 ^(@)` and electric flux ` oversetto E. oversetto oA =0. `


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