1.

A staellite in a circular orbit of raidus R has a period of 4h another satellite with orbital radius 3R around the same planet will have a period (in h)A. 16B. 4C. `4sqrt(27)`D. `4sqrt(8)`

Answer» Correct Answer - C
According to kepler s third law
`T^(2) prop R^(3) rarr (R_(2))/(R_(1))^(3//2)`
`therefore (T_(2))/(T_(1))=(3R)/(R )^(3//2)=sqrt(27)`
`therefore T_(2)=sqrt(27)T_(1)=sqrt(27)xx=s4sqrt(27)h`


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