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A standard car developes 40 H.P. Find the maximum speed the car can attain agains a resistance of 20kg wt. due to air and friction. Gvien efficiency of the engin is `25%.1H.P.=746W ` and `g=10ms^(-2)`. |
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Answer» Here, `P=40 H.P. =40xx746wat t` `v=?F=20kg wt. =20xx10N` `eta =25%, g=10m//s^(2)` As ` eta=("output power")/("input power")` `:.` output power = force `xx` velocity `:. "velocity" =("output power")/("force")` `v=(7460)/(20xx10)=37.3m//s` |
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